More AP Than DP?!? Whats Going on here

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ap dp In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ Show that: ΔAPD ≅ ΔCQB AP = CQ   AP and DP brackets are set ranges that give bonus AP or extra damage reduction For example, once you hit 100 AP, you get an extra base 5 AP   Click here:point_up_2:to get an answer to your question :writing_hand:abcd is a parallelogram p isa point on side bc such that dp produced meets

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